Soal A
- Tinggi
[tex] \tt = \sqrt{ {13}^{2} - {(10 \div 2)}^{2} } [/tex]
[tex] \tt = \sqrt{169 - {5}^{2} } [/tex]
[tex] \tt = \sqrt{169 - 25} [/tex]
[tex] \tt = \sqrt{144} [/tex]
= 12 cm
- Keliling
= 2 × 13 + 10 cm
= 26 + 10 cm
= 36 cm
- Luas
= a × t ÷ 2
= 10 cm × 12 cm ÷ 2
= 120 cm² ÷ 2
= 60 cm²
Soal B
- tinggi
[tex] \tt = \sqrt{ {10}^{2} - {6}^{2} } [/tex]
[tex] \tt = \sqrt{100 - 36} [/tex]
[tex] \tt = \sqrt{64} [/tex]
= 8 cm
- Keliling
= 8 + 6 + 10 cm
= 14 + 10 cm
= 24 cm
- Luas
= a × t ÷ 2
= 6 cm × 8 cm ÷ 2
= 48 cm² ÷ 2
= 24 cm²
Soal C
- tinggi
[tex] \tt = \sqrt{ {5}^{2} - {3}^{2} } [/tex]
[tex] \tt = \sqrt{25 - 9} [/tex]
[tex] \tt = \sqrt{16} [/tex]
= 4 cm
- Keliling
= 14 + 8 + 5 cm
= 22 + 5 cm
= 27 cm
- Luas
= L.∆Besar - L.∆kecil
= (11 × 4 ÷ 2) - (3 × 4 ÷ 2)
= 22 - 6 cm²
= 16 cm²
[tex] \pink{\boxed{\red{\boxed{\purple{\mathfrak{\ast ~ \blue{Celia ~ Claire} ~ \ast}}}}}}[/tex]
[answer.2.content]
